Solve the inequality.
-$x ^ { 2 } - 3 x \geq 0$
A) $x \leq - 3 \text { or } x \geq 0$
B) $- 3 \leq x \leq 0$
C) $x \leq 0 \text { or } x \geq 3$
D) $0 \leq x \leq 3$

Question

Quizplus · Accepted Answer

To solve the inequality $x^2 - 3x \geq 0$, factor out an $x$ to get $x(x - 3) \geq 0$. This gives us two critical points: $x = 0$ and $x = 3$. Testing intervals around these points, we find that the inequality holds for $x \leq 0$ and $x \geq 3$.

Solve the Inequality x2−3x≥0x ^ { 2 } - 3 x \geq 0x2−3x≥0

Solve the Inequality $x ^ { 2 } - 3 x \geq 0$