Use the quadratic formula or graphing methods to
-$$8 x ^ { 2 } - 36 x + 8 \leq 0$$
A) $x \geq \frac { 9 + \sqrt { 65 } } { 4 } \approx 4.266$
B) $\frac { 9 - \sqrt { 65 } } { 4 } \approx 0.234 \leq x \leq \frac { 9 + \sqrt { 65 } } { 4 } \approx 4.266$
C) $x \leq \frac { 9 - \sqrt { 65 } } { 4 } \approx 0.234$
D) $x \leq \frac { 9 - \sqrt { 65 } } { 4 } \approx 0.234$ or $x \geq \frac { 9 + \sqrt { 65 } } { 4 } \approx 4.266$

Question

Quizplus · Accepted Answer

The quadratic formula $\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ applied to $8x^2 - 36x + 8 \leq 0$ gives the roots $\frac{9 \pm \sqrt{65}}{4}$. Since it's a "less than or equal to" inequality and the parabola opens upwards (a positive leading coefficient), the solution includes values between these roots.

Use the Quadratic Formula or Graphing Methods to - 8x2−36x+8≤08 x ^ { 2 } - 36 x + 8 \leq 08x2−36x+8≤0

Use the Quadratic Formula or Graphing Methods to
- $8 x ^ { 2 } - 36 x + 8 \leq 0$