Calculate the mean of the grouped data from the given frequency distribution. (Round to nearest tenth) $$\begin{array} { | l | l | }
\hline \text { Class } & \text { Frequency } ( f ) \
\hline 200 \text { to } 249 & 3 \
\hline 250 \text { to } 299 & 1 \
\hline 300 \text { to } 349 & 1 \
\hline 350 \text { to } 399 & 3 \
\hline 400 \text { to } 449 & 1 \
\hline 450 \text { to } 499 & 3 \
\hline
\end{array}$$
A) 353.7
B) 286.5
C) 253.7
D) 250.0

Question

Calculate the mean of the grouped data from the given frequency distribution. (Round to nearest tenth) $$\begin{array} { | l | l | } 
\hline \text { Class } & \text { Frequency } ( f ) \
\hline 200 \text { to } 249 & 3 \
\hline 250 \text { to } 299 & 1 \
\hline 300 \text { to } 349 & 1 \
\hline 350 \text { to } 399 & 3 \
\hline 400 \text { to } 449 & 1 \
\hline 450 \text { to } 499 & 3 \
\hline
\end{array}$$
A) 353.7
B) 286.5
C) 253.7
D) 250.0

Quizplus · Accepted Answer

To calculate the mean of the grouped data, first find the midpoint of each class by averaging the upper and lower bounds. Then, multiply each midpoint by the class frequency to find the "weighted" midpoints. Sum these products and divide by the total frequency to get the mean.Midpoints: (224.5, 274.5, 324.5, 374.5, 424.5, 474.5)Weighted midpoints: (673.5, 274.5, 324.5, 1123.5, 424.5, 1423.5)Total frequency: 12Sum of weighted midpoints: 4244Mean = 4244 / 12 = 353.666...Rounded to the nearest tenth: 353.7

Calculate the Mean of the Grouped Data from the Given