Calculate the mean of the grouped data from the given frequency distribution. (Round your answer to the nearest tenth) $$\begin{array} { | l | l | }
\hline \text { Class } & \text { Frequency } ( f ) \
\hline 20 \text { to } 29 & 1 \
\hline 30 \text { to } 39 & 3 \
\hline 40 \text { to } 49 & 3 \
\hline 50 \text { to } 59 & 1 \
\hline 60 \text { to } 69 & 1 \
\hline 70 \text { to } 79 & 1 \
\hline
\end{array}$$
A) 27.0
B) 45.5
C) 32.4
D) 49.5

Question

Calculate the mean of the grouped data from the given frequency distribution. (Round your answer to the nearest tenth) $$\begin{array} { | l | l | } 
\hline \text { Class } & \text { Frequency } ( f ) \
\hline 20 \text { to } 29 & 1 \
\hline 30 \text { to } 39 & 3 \
\hline 40 \text { to } 49 & 3 \
\hline 50 \text { to } 59 & 1 \
\hline 60 \text { to } 69 & 1 \
\hline 70 \text { to } 79 & 1 \
\hline
\end{array}$$
A) 27.0
B) 45.5
C) 32.4
D) 49.5

Quizplus · Accepted Answer

To calculate the mean of the grouped data, first find the midpoint of each class by averaging the upper and lower bounds. Then, multiply each midpoint by the class frequency and sum these products. Finally, divide by the total frequency.Midpoints: (20+29)/2 = 24.5, (30+39)/2 = 34.5, (40+49)/2 = 44.5, (50+59)/2 = 54.5, (60+69)/2 = 64.5, (70+79)/2 = 74.5.Multiplying each midpoint by its frequency and summing: (24.5*1) + (34.5*3) + (44.5*3) + (54.5*1) + (64.5*1) + (74.5*1) = 24.5 + 103.5 + 133.5 + 54.5 + 64.5 + 74.5 = 455.Total frequency = 1 + 3 + 3 + 1 + 1 + 1 = 10.Mean = 455 / 10 = 45.5.

Calculate the Mean of the Grouped Data from the Given