Calculate the mean of the grouped data from the given frequency distribution. (Round your answer to the nearest tenth) $$\begin{array} { | l | l | }
\hline \text { Class } & \text { Frequency } ( f ) \
\hline 300 \text { to } 399 & 2 \
\hline 400 \text { to } 499 & 1 \
\hline 500 \text { to } 599 & 4 \
\hline 600 \text { to } 699 & 3 \
\hline 700 \text { to } 799 & 1 \
\hline
\end{array}$$
A) 225.3
B) 549.5
C) 272.3
D) 449.5

Question

Calculate the mean of the grouped data from the given frequency distribution. (Round your answer to the nearest tenth) $$\begin{array} { | l | l | } 
\hline \text { Class } & \text { Frequency } ( f ) \
\hline 300 \text { to } 399 & 2 \
\hline 400 \text { to } 499 & 1 \
\hline 500 \text { to } 599 & 4 \
\hline 600 \text { to } 699 & 3 \
\hline 700 \text { to } 799 & 1 \
\hline
\end{array}$$
A) 225.3
B) 549.5
C) 272.3
D) 449.5

Quizplus · Accepted Answer

To calculate the mean of the grouped data, first find the midpoint of each class by averaging the upper and lower bounds. Then, multiply each midpoint by the class frequency and sum these products. Finally, divide by the total frequency. The calculation is as follows:- Midpoint of 300 to 399 = (300 + 399) / 2 = 349.5- Midpoint of 400 to 499 = (400 + 499) / 2 = 449.5- Midpoint of 500 to 599 = (500 + 599) / 2 = 549.5- Midpoint of 600 to 699 = (600 + 699) / 2 = 649.5- Midpoint of 700 to 799 = (700 + 799) / 2 = 749.5Multiplying each midpoint by its frequency and summing:- $349.5 \times 2 = 699$- $449.5 \times 1 = 449.5$- $549.5 \times 4 = 2198$- $649.5 \times 3 = 1948.5$- $749.5 \times 1 = 749.5$Sum = $699 + 449.5 + 2198 + 1948.5 + 749.5 = 6044.5$Total frequency = $2 + 1 + 4 + 3 + 1 = 11$Mean = $6044.5 / 11 = 549.5$

Calculate the Mean of the Grouped Data from the Given