The Iodine "Clock Reaction" Involves the Following Sequence of Reactions $\rightarrow$

The iodine "clock reaction" involves the following sequence of reactions occurring in a reaction mixture in a single beaker.
1. IO₃¯(aq) + 5I¯(aq) + 6H⁺(aq) $\rightarrow$ 3I₂(aq) + 3H₂O(l)
2. I₂(aq) + 2S₂O₃²¯(aq) $\rightarrow$ 2I¯(aq) + S₄O₆²¯(aq)
The molecular iodine (I₂) formed in reaction 1 is immediately used up in reaction 2, so that no iodine accumulates. What is the overall reaction occurring in this experiment?

A) IO₃¯(aq) + 3I¯(aq) + 2S₂O₃²¯(aq) + 6H⁺(aq) $\rightarrow$ 2I₂(aq) + S₄O₆²¯(aq) + 3H₂O(l)
B) IO₃¯(aq) + 4S₂O₃²¯(aq) + 6H⁺(aq) $\rightarrow$ I¯(aq) + 2S₄O₆²¯(aq) + 3H₂O(l)
C) IO₃¯(aq) + 6S₂O₃²¯(aq) + 6H⁺(aq) $\rightarrow$ I¯(aq) + 3S₄O₆²¯(aq) + 3H₂O(l)
D) IO₃¯(aq) + I₂(aq) + 8S₂O₃²¯(aq) + 6H⁺(aq) $\rightarrow$ 3I¯(aq) + 4S₄O₆²¯(aq) + 3H₂O(l)
E) IO₃¯(aq) + 2I₂(aq) + 6S₂O₃²¯(aq) + 6H⁺(aq) $\rightarrow$ 5I¯(aq) + 3S₄O₆²¯(aq) + 3H₂O(l)