Phosphine, an extremely poisonous and highly reactive gas, will react with oxygen to form tetraphosphorus decaoxide and water. PH₃(g) + O₂(g) $\to$ P₄O₁₀(s) + H₂O(g) [unbalanced]
Calculate the mass of P₄O₁₀(s) formed when 225 g of PH₃reacts with excess oxygen.

Question

Phosphine, an extremely poisonous and highly reactive gas, will react with oxygen to form tetraphosphorus decaoxide and water. PH₃(g) + O₂(g)

\to

P₄O₁₀(s) + H₂O(g) [unbalanced]
Calculate the mass of P₄O₁₀(s) formed when 225 g of PH₃reacts with excess oxygen.

Quizplus · Accepted Answer

First, balance the chemical equation: 4PH₃ + 8O₂ → P₄O₁₀ + 6H₂O. Calculate moles of PH₃: 225 g / 34.00 g/mol = 6.618 moles. From the balanced equation, 4 moles of PH₃ produce 1 mole of P₄O₁₀. Thus, 6.618 moles PH₃ produce 6.618/4 = 1.6545 moles P₄O₁₀. Calculate mass of P₄O₁₀: 1.6545 moles × 283.88 g/mol = 470 g.

Phosphine, an Extremely Poisonous and Highly Reactive Gas, Will React →\to→

Phosphine, an Extremely Poisonous and Highly Reactive Gas, Will React $\to$