Aluminum will react with bromine to form aluminum bromide (used as an acid catalyst in organic synthesis) . Al(s) + Br₂(l) $\to$ Al₂Br₆(s) [unbalanced]
How many moles of Al are needed to form 2.43 mol of Al₂Br₆?

Question

Aluminum will react with bromine to form aluminum bromide (used as an acid catalyst in organic synthesis) . Al(s) + Br₂(l)

\to

Al₂Br₆(s) [unbalanced]
How many moles of Al are needed to form 2.43 mol of Al₂Br₆?

Quizplus · Accepted Answer

Based on the balanced chemical equation, it takes 2 moles of Al to form 2 moles of Al₂Br₆. Therefore, to form 1 mole of Al₂Br₆, it takes 1 mole of Al. To form 2.43 moles of Al₂Br₆, it will take 2.43 moles of Al, which is equivalent to choice B.

Aluminum Will React with Bromine to Form Aluminum Bromide (Used →\to→

Aluminum Will React with Bromine to Form Aluminum Bromide (Used $\to$