What volume of water must be added to 300 mL of 0.75 M HCl to dilute the solution to 0.25 M?
A) 900 mL
B) 600 mL
C) 300 mL
D) 930 mL
E) 100 mL

Question

Quizplus · Accepted Answer

M1V1 = M2V2

where,

M1 = initial concentration
V1 = initial volume
M2 = final concentration
V2 = final volume

Here,

M1 = 0.75 M
V1 = 300 mL
M2 = 0.25 M
V2 = ?

Substituting the values,

0.75 M x 300 mL = 0.25 M x V2

225 = 0.25V2

V2 = 900 mL

Therefore, the volume of water that must be added = V2 - V1 = 900 mL - 300 mL = 600 mL

Hence, the correct choice is B.

What Volume of Water Must Be Added to 300 ML