A 34.62-mL sample of 0.1510 M NaOH was needed to neutralize 50.0 mL of an H₂SO₄ solution. What is the concentration of the original sulfuric acid solution? A) 0.0229 M B) 0.218 M C) 0.0523 M D) 0.209 M E) 0.105 M

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Quizplus · Accepted Answer

The balanced equation for the reaction is 2 NaOH + H2SO4 → Na2SO4 + 2 H2O. Calculate moles of NaOH: 0.03462 L * 0.1510 mol/L = 0.00523 mol. Since the ratio is 2:1, moles of H2SO4 = 0.00523 mol / 2 = 0.002615 mol. Concentration of H2SO4 = 0.002615 mol / 0.0500 L = 0.0523 M.

A 3462-ML Sample of 0