Octane (C8H18) undergoes combustion according to the following thermochemical equation. 2C8H18(l) + 25O2(g) → 16CO2(g) + 18H2O(l) ΔH°rxn = -1.0940 × 104 kJ/mol
What is the standard enthalpy of formation of liquid octane?
ΔH°f(CO2(g) ) = -393.5 kJ/mol and ΔH°f(H2O(l) ) = -285.8 kJ/mol
A) -250 kJ/mol
B) -10,940. kJ/mol
C) -2188 kJ/mol
D) -495 kJ/mol
E) 495 kJ/mol
Correct Answer:
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