Based on the following thermochemical equations, what is the heat of vaporization of titanium(IV) chloride? Ti(s) + 2 Cl₂(g) → TiCl₄(l) ΔH = -804.2 kJ/mol
TiCl₄(g) → 2 Cl₂(g) + Ti(s) ΔH = 763.2 kJ/mol

Question

Quizplus · Accepted Answer

To find the heat of vaporization of titanium(IV) chloride (TiCl4), we need to reverse the first reaction and add it to the second. Reversing the first reaction changes the sign of ΔH to +804.2 kJ/mol. Adding this to the ΔH of the second reaction (763.2 kJ/mol) gives a total ΔH of +41.0 kJ/mol for the vaporization of TiCl4.

Based on the Following Thermochemical Equations, What Is the Heat