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Management Science Study Set 1
Quiz 20: Nonlinear Programming: Solution Techniques
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Question 21
Short Answer
If a nonlinear programming problem results in profit (Z) of $250, and the Lagrange multiplier for a constraint is 5, the new profit will be ________ if the right-hand side of the constraint is decreased by 1 unit.
Question 22
Multiple Choice
The slope of a curve at its highest point equals:
Question 23
Short Answer
In solving a maximization problem, the optimal profit associated with the relaxed solution is always less than or equal to the value of the optimal profit associated with the ________ solution.
Question 24
Essay
A customer molder produces 6-ounce juice glasses and 10-ounce cocktail glasses. The per unit contribution for the juice glasses (x
1
) is equal to 60 - 5x
1
, and the per unit contribution for the cocktail glasses (x
2
) is 80 - 4x
2
for a total contribution of 60x
1
- 5x
1
2
+ 80x
2
- 4x
2
2
. Demand requires that the production of juice glasses is twice the production of cocktail glasses.(x1 = 2x
2
). What is the Lagrangian function for this problem?
Question 25
Essay
Given the nonlinear programming model Max Z = 4x
1
- 0.1x
1
x
2
+ 5x
2
- 0.2 x
2
2
Subject to: x
1
+ 2x
2
= 4 What is the Lagrangian function?
Question 26
Short Answer
Given the nonlinear programming model Max Z = 5x
1
- 2x
2
2
Subject to: x
1
+ x
2
= 6 What is the Lagrangian function?
Question 27
Short Answer
A customer molder produces 6-ounce juice glasses and 10-ounce cocktail glasses. The per unit contribution for the juice glasses (x
1
) is equal to 60 - 5x
1
, and the per unit contribution for the cocktail glasses (x
2
) is 80 - 4 x
2
for a total contribution of 60x
1
- 5x
1
2
+ 80x
2
- 4x
2
2. Demand requires that the production of juice glasses is twice the production of cocktail glasses (x
1
= 2x
2
). Write the objective function for this problem which illustrates the technique of substitution.
Question 28
Essay
Write the Lagrangian function for the following nonlinear program: Min x1
2
+ 2x
2
2
- 8x
1
- 12x
1
+ 34 subject to: x1
2
+ 2x
2
2
= 5