The specific heat capacity of liquid water is 4.18 J/g ^oC. Calculate the quantity of energy required to heat 10.4 g of water from 26.5^oC to 83.7^oC. A) J B) J C) 23.9 J D) J E) none of these

Question

Quizplus · Accepted Answer

The equation to use is:
q = m * c * ΔT
where q is the quantity of energy required, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. Plugging in the given values, we get:
q = (10.4 g) * (4.18 J/g°C) * (83.7°C - 26.5°C)
q = 11,840.24 J = 1.18 * 10^4 J = 11eab077_f80f_99ba_beed_d31b208a4c48_TB6421_11 J (to 3 significant figures)
Therefore, the best choice is D.

The Specific Heat Capacity of Liquid Water Is 4