Calculate the quantity of energy required to change 22.8 g of liquid water to steam at 100^oC. The molar heat of vaporization of water is 40.6 kJ/mol. A) 10.1 kJ B) 51.4 kJ C) 0.562 kJ D) 32.1 kJ E) kJ

Question

Quizplus · Accepted Answer

First, we need to calculate the number of moles of water:
n = m/MW = 22.8 g / 18.015 g/mol = 1.266 mol
Next, we can use the formula:
q = n x ΔHvap
where q is the quantity of energy required and ΔHvap is the molar heat of vaporization. Substituting the values:
q = 1.266 mol x 40.6 kJ/mol = 51.4 kJ
Therefore, the correct choice is (B).

Calculate the Quantity of Energy Required to Change 22