You have three sodium carbonate solutions on a lab table in front of you. All of the solutions came from a 500.0-mL volumetric flask containing 3.00 M sodium carbonate. Solution 1 contains 100.0 mL of the 3.00 M solution.
Solution 2 contains 50.0 mL of the 3.00 M solution.
Solution 3 contains 10.0 mL of the 3.00 M solution.
What volume of water (in mL) must evaporate from Solution 1 in order to have a concentration of 4.48 M?
A) 67.0 mL
B) 49.3 mL
C) 33.0 mL
D) 14.9 mL
E) 85.1 mL

Question

Quizplus · Accepted Answer

We can use the formula:

C1V1 = C2V2

where C1 and V1 are the initial concentration and volume, and C2 and V2 are the final concentration and volume.

For Solution 1, we have:

C1 = 3.00 M
V1 = 100.0 mL
C2 = 4.48 M
V2 = ?

Plugging in the values, we get:

(3.00 M)(100.0 mL) = (4.48 M)(V2)

V2 = (3.00 M)(100.0 mL) / (4.48 M)

V2 = 66.96 mL

So the volume of Solution 1 that needs to be evaporated is:

100.0 mL - 66.96 mL = 33.04 mL

Therefore, the answer is choice C, 33.0 mL.

You Have Three Sodium Carbonate Solutions on a Lab Table