You mix 100.0 mL of a 0.100 M NaOH solution and 150.0 mL of a 0.104 M HCl solution. Determine the concentration of H⁺ in the final mixture after the reaction is complete. A) 0.0624 M B) 0.104 M C) 0.156 M D) 0.204 M E) 0.0224 M

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Quizplus · Accepted Answer

First, calculate the moles of NaOH and HCl. Moles of NaOH = 0.100 M * 0.100 L = 0.0100 moles. Moles of HCl = 0.104 M * 0.150 L = 0.0156 moles. HCl is in excess, so subtract moles of NaOH from HCl to find excess HCl moles: 0.0156 - 0.0100 = 0.0056 moles. The total volume after mixing is 100.0 mL + 150.0 mL = 250.0 mL or 0.250 L. The concentration of excess HCl is 0.0056 moles / 0.250 L = 0.0224 M.

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