What mass of calcium chloride, CaCl₂, is needed to prepare 2.657 L of a 1.56 M solution? A) 4.14 g B) 313 g C) 189 g D) 65.2 g E) 460 g

Question

Quizplus · Accepted Answer

First, we need to calculate the amount of moles of CaCl2 needed to prepare the solution:

2.657 L x 1.56 mol/L = 4.14192 mol

Then, we can use the molar mass of CaCl2 to convert moles to grams:

4.14192 mol x 110.98 g/mol = 457.99 g

Rounding to significant figures, the mass of CaCl2 needed is 460 g, which is answer choice E.

What Mass of Calcium Chloride, CaCl2, Is Needed to Prepare