In the circuit shown, both resistors have the same value R. Suppose switch S is initially closed and capacitor C is charged. When switch S is then opened, the circuit has a time constant $ \tau $_a. Conversely, suppose S is initially open and capacitor C is uncharged. When switch S is then closed, the circuit has a time constant $ \tau $_b. The ratio $ \tau $_a/ $ \tau $_b is: A) 0.5 B) 0.67 C) 1 D) 1.5 E) 2

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The Answer of In the circuit shown, both resistors have the same value R. Suppose switch S is initially closed and capacitor C is charged. When switch S is then opened, the circuit has a time constant $ \tau $_a. Conversely, suppose S is initially open and capacitor C is uncharged. When switch S is then closed, the circuit has a time constant $ \tau $_b. The ratio $ \tau $_a/ $ \tau $_b is: A) 0.5 B) 0.67 C) 1 D) 1.5 E) 2

In the Circuit Shown, Both Resistors Have the Same Value τ \tau τ

In the Circuit Shown, Both Resistors Have the Same Value $\tau$