Chromate ion is added to a saturated solution of Ag₂CrO₄ to reach 0.10 M CrO₄^2-. Calculate the final concentration of silver ion at equilibrium (K_sp for Ag₂CrO₄ is 9.0 × 10^-12). A) 9.5 × 10^-6 M B) 1.7 × 10^-6 M C) 5.5 × 10^-11 M D) 6.6 × 10^-6 M E) 1.1 × 10^-13 M

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Quizplus · Accepted Answer

The solubility product expression for Ag₂CrO₄ is Ksp = [Ag⁺]²[CrO₄²⁻]. Given Ksp = 9.0 × 10⁻¹² and [CrO₄²⁻] = 0.10 M, solve for [Ag⁺]: [Ag⁺]² = Ksp / [CrO₄²⁻] = 9.0 × 10⁻¹² / 0.10 = 9.0 × 10⁻¹¹. Thus, [Ag⁺] = √(9.0 × 10⁻¹¹) = 9.5 × 10⁻⁶ M.

Chromate Ion Is Added to a Saturated Solution of Ag2CrO4

Chromate Ion Is Added to a Saturated Solution of Ag₂CrO₄