The value of K_sp for AgI is 1.5 × 10^-16. Calculate the solubility, in moles per liter, of AgI in a 0.28 M NaI solution. A) 1.2 × 10^-8 mol/L B) 5.4 × 10^-16 mol/L C) 2.1 × 10^-9 mol/L D) 4.2 × 10^-17 mol/L E) 2.3 × 10^-8 mol/L

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Quizplus · Accepted Answer

The solubility of AgI in a NaI solution is governed by the common ion effect. The presence of I- ions from NaI decreases the solubility of AgI. The solubility product (Ksp) for AgI is given as 1.5 × 10^-16. In a solution with NaI, the concentration of I- ions is no longer variable but fixed at 0.28 M. The solubility of AgI, s, can be calculated using the formula Ksp = [Ag+][I-], where [I-] = 0.28 M. Since Ksp = 1.5 × 10^-16 = s(0.28), solving for s gives a value much smaller than the initial concentration of I- ions, indicating the solubility is significantly reduced due to the common ion effect. The correct calculation should reflect this significant reduction, leading to a very small solubility value.

The Value of Ksp for AgI Is 1

The Value of K_sp for AgI Is 1