Calculate the solubility of Ca₃(PO₄)₂(s) (K_sp = 1.3 × 10^-32) in a 1.0 × 10^-2 M Ca(NO₃)₂ solution. A) 3.16 × 10^-12 mol/L B) 5.7 × 10^-14 mol/L C) 6.2 × 10^-7 mol/L D) 1.6 × 10^-14 mol/L E) none of these

Question

Quizplus · Accepted Answer

The solubility product expression for Ca₃(PO₄)₂ is Ksp = [Ca²⁺]³[PO₄³⁻]². In a 1.0 × 10⁻² M Ca(NO₃)₂ solution, [Ca²⁺] is 0.01 + 3s, where s is the solubility of Ca₃(PO₄)₂. Assuming s is small, [Ca²⁺] ≈ 0.01. Solving Ksp = (0.01)³(2s)² for s gives s ≈ 5.7 × 10⁻¹⁴ mol/L.

Calculate the Solubility of Ca3(PO4)2(s) (Ksp = 1

Calculate the Solubility of Ca₃(PO₄)₂(s) (K_sp = 1