Calculate the concentration of chromate ion, CrO₄^2-, in a saturated solution of CaCrO₄ (K_sp = 7.1 × 10^-4). A) 5.0 × 10^-7 M B) 3.5 × 10^-2 M C) 0.027 M D) 3.5 × 10^-4 M E) 7.1 × 10^-4 M

Question

Quizplus · Accepted Answer

The solubility product expression for CaCrO₄ is Ksp = [Ca²⁺][CrO₄²⁻]. In a saturated solution, [Ca²⁺] = [CrO₄²⁻] = s. Therefore, Ksp = s². Solving for s, s = √(7.1 × 10⁻⁴) = 0.027 M.

Calculate the Concentration of Chromate Ion, CrO42-, in a Saturated

Calculate the Concentration of Chromate Ion, CrO₄^2-, in a Saturated