An aqueous solution contains 51.2 g of propanol (C₃H₇OH) in 123.0 g of solution. What is the mole fraction of propanol? A) 0.176 B) 0.294 C) 0.272 D) 0.214 E) 0.824

Question

Quizplus · Accepted Answer

The mole fraction of a component in a solution is calculated by dividing the moles of that component by the total moles of all components in the solution. First, calculate the moles of propanol (C3H8O) using its molar mass (60.1 g/mol): moles of propanol = 51.2 g / 60.1 g/mol = 0.852 moles. The mass of water in the solution is 123.0 g - 51.2 g = 71.8 g. The moles of water = 71.8 g / 18.015 g/mol (molar mass of water) = 3.986 moles. Total moles = 0.852 moles (propanol) + 3.986 moles (water) = 4.838 moles. The mole fraction of propanol = moles of propanol / total moles = 0.852 / 4.838 ≈ 0.176.

An Aqueous Solution Contains 51