How many milliliters of 11.8 M HNO₃ are needed to prepare 386.2 mL of 0.18 M HNO₃? A) 2.5 × 10¹ mL B) 0.310 mL C) 0.030 mL D) 5.9 mL E) 40 mL

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Quizplus · Accepted Answer

The equation to use is: M1V1 = M2V2 where M1 = 11.8 M (initial concentration) V1 = what we want to find (volume of 11.8 M HNO₃ needed) M2 = 0.18 M (final concentration) V2 = 386.2 mL (final volume) Rearranging the equation, we get: V1 = M2V2/M1 V1 = (0.18 M)(386.2 mL)/(11.8 M) V1 = 5.89 mL Therefore, we need 5.89 mL of 11.8 M HNO₃ to prepare 386.2 mL of 0.18 M HNO₃. The closest choice is D: 5.9 mL.

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