When 228.8 mL of 0.726 MHCl is diluted with 122.2 mL of water, the molarity of the solution (assuming the volumes are additive) is
A) 0.473 M.
B) 0.115 M.
C) 0.00207 M.
D) 0.253 M.
E) 1.36 M.

Question

Quizplus · Accepted Answer

The molarity after dilution can be calculated using the formula $M_1V_1 = M_2V_2$, where $M_1$ and $V_1$ are the molarity and volume of the initial solution, and $M_2$ and $V_2$ are the molarity and volume of the final solution, respectively. Here, $M_1 = 0.726 M$, $V_1 = 228.8 mL$, and $V_2 = 228.8 mL + 122.2 mL = 351 mL$. Solving for $M_2$, we get $M_2 = \frac{M_1V_1}{V_2} = \frac{0.726 M \times 228.8 mL}{351 mL} = 0.473 M$.

When 2288 ML of 0