Calculate the molality of a solution containing 22.4 g of C₆H₁₂O₆ in 319.6 mL of water (assume a density of 1.00 g/mL). A) 0.364 m B) 0.0655 m C) 0.000389 m D) 0.389 m E) 0.00695 m

Question

Quizplus · Accepted Answer

To calculate molality, first find the moles of C6H12O6: Molar mass = 180.18 g/mol, so moles = 22.4 g / 180.18 g/mol = 0.1243 mol. The mass of water is 319.6 g (since density is 1.00 g/mL). Molality = moles of solute / kg of solvent = 0.1243 mol / 0.3196 kg = 0.389 m.

Calculate the Molality of a Solution Containing 22