What is the molarity of a saturated solution of potassium sulfate if the solubility is 13 g per 100 g H₂O at 25°C? The density of the solution is 1.1 g/mL A) 0.14 M B) 1.1 M C) 0.96 M D) 0.73 M E) 0.79 M

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Quizplus · Accepted Answer

To find the molarity, first calculate the moles of K2SO4 in 13 g. The molar mass of K2SO4 is approximately 174 g/mol, so 13 g is about 0.075 mol. The solution's total mass is 113 g (100 g water + 13 g K2SO4), and its volume is 113 g / 1.1 g/mL = 102.73 mL = 0.10273 L. Molarity = moles/volume = 0.075 mol / 0.10273 L ≈ 0.73 M.

What Is the Molarity of a Saturated Solution of Potassium