252 mL of 3.00 M H₂SO₄are added to 1.50 L of 0.500 M H₂SO₄. What is the concentration of the resulting solution? A) 1.50 M B) 0.860 M C) 2.64 M D) 1.75 M E) 1.25 M

Question

Quizplus · Accepted Answer

We can use the equation: M1V1 + M2V2 = M3V3 where M1 = 3.00 M (initial concentration of H₂SO₄) V1 = 252 mL = 0.252 L (volume of H₂SO₄ added) M2 = 0.500 M (initial concentration of H₂SO₄) V2 = 1.50 L (volume of H₂SO₄ the solution was added to) M3 = unknown concentration of resulting solution V3 = V1 + V2 = 1.752 L (total volume of resulting solution) Plugging in the values, we get: (3.00 M)(0.252 L) + (0.500 M)(1.50 L) = M3(1.752 L) 0.756 + 0.750 = M3(1.752) M3 = 0.860 M Therefore, the concentration of the resulting solution is 0.860 M, which corresponds to choice (B).

252 ML of 3