An aqueous solution contains 64.0 g of ethanol (C₂H₅OH) in 122.0 g of solution. What is the mole fraction of ethanol in the solution? A) 0.301 B) 0.432 C) 0.205 D) 0.698 E) 0.317

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Quizplus · Accepted Answer

To find the mole fraction of ethanol, first calculate the moles of ethanol: 64.0 g / 46.08 g/mol = 1.39 mol. The mass of water is 122.0 g - 64.0 g = 58.0 g, and the moles of water are 58.0 g / 18.02 g/mol = 3.22 mol. The mole fraction of ethanol is 1.39 mol / (1.39 mol + 3.22 mol) = 0.301.

An Aqueous Solution Contains 64