Arrange the following three water solutions (all 250 cm3 in volume) according to decreasing osmotic pressure at 273 K: 5 g of C₂H₅OH, 5 g C₆H₁₂O₆ ,and 5 g C₁₂H₂₂O₁₁. A) C₂H₅OH C₆H₁₂O₆ C₁₂H₂₂O₁₁. B) C₂H₅OH C₆H₁₂O₆= C₁₂H₂₂O₁₁. C) C₆H₁₂O₆ C₂H₅OH C₁₂H₂₂O₁₁. D) C₁₂H₂₂O₁₁. C₆H₁₂O₆ C₂H₅OH E) C₁₂H₂₂O₁₁. C₂H₅OH C₆H₁₂O₆

Question

Arrange the following three water solutions (all 250 cm3 in volume) according to decreasing osmotic pressure at 273 K: 5 g of C₂H₅OH, 5 g C₆H₁₂O₆ ,and 5 g C₁₂H₂₂O₁₁. A) C₂H₅OH > C₆H₁₂O₆ > C₁₂H₂₂O₁₁. B) C₂H₅OH> C₆H₁₂O₆= C₁₂H₂₂O₁₁. C) C₆H₁₂O₆ > C₂H₅OH> C₁₂H₂₂O₁₁. D) C₁₂H₂₂O₁₁. > C₆H₁₂O₆ > C₂H₅OH E) C₁₂H₂₂O₁₁. > C₂H₅OH> C₆H₁₂O₆

Quizplus · Accepted Answer

The osmotic pressure of a solution is directly proportional to the concentration of solute particles in the solution. The more solute particles a solution contains, the lower its water potential, and the higher its osmotic pressure. All three solutions have the same volume and contain the same type of solute, but differ in the number of solute particles. Among the given compounds, C₂H₅OH has the smallest molecular formula, and hence the lowest number of solute particles. On the other hand, C₁₂H₂₂O₁₁ has the largest molecular formula among the given compounds, and hence the highest number of solute particles. Therefore, the correct order from highest to lowest osmotic pressure is C₂H₅OH > C₆H₁₂O₆ > C₁₂H₂₂O₁₁.

Arrange the Following Three Water Solutions (All 250 Cm3 in Volume)