Consider the reaction:
N₂O₄(g) → 2 NO₂(g) Keq = 0.1134 at 20 °C. ΔH°rxn = 58.03 kJ/mol
What is ΔG° for this reaction at 20 °C?

Question

Consider the reaction: N₂O₄(g) → 2 NO₂(g) Keq = 0.1134 at 20 °C. ΔH°rxn = 58.03 kJ/mol What is ΔG° for this reaction at 20 °C? A) 0.36 kJ B) -5.4 kJ C) 4.9 kJ D) 5.3 kJ E) 5.4 kJ

Quizplus · Accepted Answer

ΔG° = -RTlnKeq
where R = 8.314 J/molK, T = 20 + 273 = 293 K, and Keq = 0.1134
ΔG° = -(8.314 J/molK)(293 K)ln(0.1134) /1000 J/kJ
ΔG° = 5.3 kJ/mol (rounded to one decimal place)

Consider the Reaction