Consider the following reaction:
S₂Cl₂(g) + 2 OCl₂(g) → 2 SOCl₂(g) + Cl₂(g)
ΔG°f -32 97.9 -320 0.0 kJ/mol
What is Keq for this reaction at 25 °C?

Question

Quizplus · Accepted Answer

The standard Gibbs free energy change (ΔG°) for the reaction can be calculated using the formula ΔG° = ΣΔG°f(products) - ΣΔG°f(reactants). Using the given ΔG°f values, ΔG° = [2(-320) + 0] - [-32 + 2(97.9)] = -648 kJ/mol. The equilibrium constant (Keq) is related to ΔG° by the equation ΔG° = -RTln(Keq). Solving for Keq gives Keq = e^(ΔG°/RT). At 25°C (298 K), R = 8.314 J/mol·K, so Keq = e^(648000/(8.314*298)) = e^324.

Consider the Following Reaction