Show that $\int _ { C } 2 x d x + 2 y d y + 2 z d z = \mathbf { a } \cdot \mathbf { a }$ , where $\mathbf { a } = a _ { 1 } \mathbf { i } + a _ { 2 } \mathbf { j } + a _ { 3 } \mathbf { k }$ , and C is any path from $( 0,0,0 )$ to $\left( a _ { 1 } , a _ { 2 } , a _ { 3 } \right)$ .

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The Answer of Show that $\int _ { C } 2 x d x + 2 y d y + 2 z d z = \mathbf { a } \cdot \mathbf { a }$ , where $\mathbf { a } = a _ { 1 } \mathbf { i } + a _ { 2 } \mathbf { j } + a _ { 3 } \mathbf { k }$ , and C is any path from $( 0,0,0 )$ to $\left( a _ { 1 } , a _ { 2 } , a _ { 3 } \right)$ .

Show That ∫C2xdx+2ydy+2zdz=a⋅a\int _ { C } 2 x d x + 2 y d y + 2 z d z = \mathbf { a } \cdot \mathbf { a }∫C​2xdx+2ydy+2zdz=a⋅a

Show That $\int _ { C } 2 x d x + 2 y d y + 2 z d z = \mathbf { a } \cdot \mathbf { a }$