Consider the curve given by $x = 2 \sin t + 5 , y = 4 - 5 \cos t , 0 \leq t \leq 2 \pi$ Find $\frac { d y } { d x }$ at the point corresponding to $t = \frac { 5 \pi } { 4 }$

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The Answer of Consider the curve given by $x = 2 \sin t + 5 , y = 4 - 5 \cos t , 0 \leq t \leq 2 \pi$ Find $\frac { d y } { d x }$ at the point corresponding to $t = \frac { 5 \pi } { 4 }$

Consider the Curve Given By x=2sin⁡t+5,y=4−5cos⁡t,0≤t≤2πx = 2 \sin t + 5 , y = 4 - 5 \cos t , 0 \leq t \leq 2 \pix=2sint+5,y=4−5cost,0≤t≤2π

Consider the Curve Given By $x = 2 \sin t + 5 , y = 4 - 5 \cos t , 0 \leq t \leq 2 \pi$