The position of a particle moving along the x-axis is given by $x = 0.08 \sin ( 12 t + 0.3 )$ meters, where t is measured in seconds.(a) Determine the position, velocity, and acceleration of the particle when t = 0.65.(b) Show that the acceleration of the particle is proportional to its position, but in the opposite direction.

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The Answer of The position of a particle moving along the x-axis is given by $x = 0.08 \sin ( 12 t + 0.3 )$ meters, where t is measured in seconds.(a) Determine the position, velocity, and acceleration of the particle when t = 0.65.(b) Show that the acceleration of the particle is proportional to its position, but in the opposite direction.

The Position of a Particle Moving Along the X-Axis Is x=0.08sin⁡(12t+0.3)x = 0.08 \sin ( 12 t + 0.3 )x=0.08sin(12t+0.3)

The Position of a Particle Moving Along the X-Axis Is $x = 0.08 \sin ( 12 t + 0.3 )$