Find $\frac { d y } { d x }$ .(a) $y = \ln \sqrt { \frac { 4 x - 7 } { x ^ { 2 } + 2 x } }$ (b) $y = ( \ln ( \sec x ) ) ^ { 4 }$ (c) $y = \left( 1 + \frac { 1 } { x } \right) ^ { 2 x }$

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The Answer of Find $\frac { d y } { d x }$ .(a) $y = \ln \sqrt { \frac { 4 x - 7 } { x ^ { 2 } + 2 x } }$ (b) $y = ( \ln ( \sec x ) ) ^ { 4 }$ (c) $y = \left( 1 + \frac { 1 } { x } \right) ^ { 2 x }$

Find dydx\frac { d y } { d x }dxdy​ (A) y=ln⁡4x−7x2+2xy = \ln \sqrt { \frac { 4 x - 7 } { x ^ { 2 } + 2 x } }y=lnx2+2x4x−7​​

Find $\frac { d y } { d x }$ (A) $y = \ln \sqrt { \frac { 4 x - 7 } { x ^ { 2 } + 2 x } }$