Find the distance from the center of the sphere whose equation is $x ^ { 2 } + 2 x + y ^ { 2 } + 4 y + z ^ { 2 } + 6 z = 0$ to the xz-plane.
A) $\sqrt { 14 }$
B)4
C) $\sqrt { 10 }$
D)3
E)1
F) $\sqrt { 13 }$
G)2
H) $\sqrt { 5 }$

Question

Find the distance from the center of the sphere whose equation is $x ^ { 2 } + 2 x + y ^ { 2 } + 4 y + z ^ { 2 } + 6 z = 0$ to the xz-plane.
A) $\sqrt { 14 }$ 
B)4
C) $\sqrt { 10 }$ 
D)3
E)1
F) $\sqrt { 13 }$ 
G)2
H) $\sqrt { 5 }$

Quizplus · Accepted Answer

The distance from the center of the sphere to the xz-plane is equal to the absolute value of the y-coordinate of the center. The center of the sphere is (-1, -2, -3), so the distance to the xz-plane is |(-2)| = 2.

Find the Distance from the Center of the Sphere Whose x2+2x+y2+4y+z2+6z=0x ^ { 2 } + 2 x + y ^ { 2 } + 4 y + z ^ { 2 } + 6 z = 0x2+2x+y2+4y+z2+6z=0

Find the Distance from the Center of the Sphere Whose $x ^ { 2 } + 2 x + y ^ { 2 } + 4 y + z ^ { 2 } + 6 z = 0$