In the previous problem, the exact solution of the initial value problem is
A) $y = \tan x$
B) $y = \sec x$
C) $y = \left( e ^ { - 2 x } - 1 \right) / \left( e ^ { - 2 x } + 1 \right)$
D) $y = - \left( e ^ { - 2 x } + 1 \right) / \left( e ^ { - 2 x } - 1 \right)$
E) $y = - \left( e ^ { 2 x } - 1 \right) / \left( e ^ { 2 x } + 1 \right)$

Question

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The Answer of In the previous problem, the exact solution of the initial value problem is
A) $y = \tan x$
B) $y = \sec x$
C) $y = \left( e ^ { - 2 x } - 1 \right) / \left( e ^ { - 2 x } + 1 \right)$
D) $y = - \left( e ^ { - 2 x } + 1 \right) / \left( e ^ { - 2 x } - 1 \right)$
E) $y = - \left( e ^ { 2 x } - 1 \right) / \left( e ^ { 2 x } + 1 \right)$

In the Previous Problem, the Exact Solution of the Initial y=tan⁡xy = \tan xy=tanx

In the Previous Problem, the Exact Solution of the Initial $y = \tan x$