Determine the zeros (if any)of the rational function $f ( x ) = \frac { x ^ { 2 } - 81 } { x + 2 }$ .
A)x = -2
B) $x = - \frac { 9 } { 2 } , x = \frac { 9 } { 2 }$
C)x = -81,x = 81
D)x = -9,x = 9
E)no zeros

Question

Quizplus · Accepted Answer

The zeros of the function are the values of $x$ for which the numerator equals zero (the denominator does not determine the zeros). The numerator is a difference of squares, $x^2 - 81 = (x - 9)(x + 9)$, which equals zero when $x = 9$ or $x = -9$.

Determine the Zeros (If Any)of the Rational Function f(x)=x2−81x+2f ( x ) = \frac { x ^ { 2 } - 81 } { x + 2 }f(x)=x+2x2−81​

Determine the Zeros (If Any)of the Rational Function $f ( x ) = \frac { x ^ { 2 } - 81 } { x + 2 }$