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Evaluate (If Possible)the Sine,cosine,and Tangent of the Real Number t=9π4t = \frac { 9 \pi } { 4 }

Question 19

Multiple Choice

Evaluate (if possible) the sine,cosine,and tangent of the real number.​ t=9π4t = \frac { 9 \pi } { 4 }


A) t=9π4t = \frac { 9 \pi } { 4 } corresponds to the point (x,y) =(22,22) ( x , y ) = \left( \frac { \sqrt { 2 } } { 2 } , - \frac { \sqrt { 2 } } { 2 } \right) . sin(9π4) =22cos(9π4) =22tan(9π4) =1\begin{array} { l } \sin \left( \frac { 9 \pi } { 4 } \right) = - \frac { \sqrt { 2 } } { 2 } \\\cos \left( \frac { 9 \pi } { 4 } \right) = \frac { \sqrt { 2 } } { 2 } \\\tan \left( \frac { 9 \pi } { 4 } \right) = - 1\end{array}
B) t=9π4t = \frac { 9 \pi } { 4 } corresponds to the point (x,y) =(22,22) ( x , y ) = \left( \frac { \sqrt { 2 } } { 2 } , \frac { \sqrt { 2 } } { 2 } \right) . sin(9π4) =22cos(9π4) =22tan(9π4) =1\begin{array} { l } \sin \left( \frac { 9 \pi } { 4 } \right) = \frac { \sqrt { 2 } } { 2 } \\\cos \left( \frac { 9 \pi } { 4 } \right) = \frac { \sqrt { 2 } } { 2 } \\\tan \left( \frac { 9 \pi } { 4 } \right) = 1\end{array}
C) t=9π4t = \frac { 9 \pi } { 4 } corresponds to the point (x,y) =(22,22) ( x , y ) = \left( - \frac { \sqrt { 2 } } { 2 } , - \frac { \sqrt { 2 } } { 2 } \right) . sin(9π4) =22cos(9π4) =22tan(9π4) =1\begin{array} { l } \sin \left( \frac { 9 \pi } { 4 } \right) = - \frac { \sqrt { 2 } } { 2 } \\\cos \left( \frac { 9 \pi } { 4 } \right) = - \frac { \sqrt { 2 } } { 2 } \\\tan \left( \frac { 9 \pi } { 4 } \right) = 1\end{array}
D) t=9π4t = \frac { 9 \pi } { 4 } corresponds to the point (x,y) =(22,22) ( x , y ) = \left( - \frac { \sqrt { 2 } } { 2 } , \frac { \sqrt { 2 } } { 2 } \right) .​ sin(9π4) =22cos(9π4) =22tan(9π4) =1\begin{array} { l } \sin \left( \frac { 9 \pi } { 4 } \right) = \frac { \sqrt { 2 } } { 2 } \\\cos \left( \frac { 9 \pi } { 4 } \right) = - \frac { \sqrt { 2 } } { 2 } \\\tan \left( \frac { 9 \pi } { 4 } \right) = - 1\end{array}
E) Not possible

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