Find the point (x,y)on the unit circle that corresponds to the real number t. $t = \frac { 19 \pi } { 3 }$
A) $t = \frac { 19 \pi } { 3 }$ corresponds to the point $\left( \frac { \sqrt { 3 } } { 2 } , \frac { 1 } { 2 } \right)$ .
B) $t = \frac { 19 \pi } { 3 }$ corresponds to the point $\left( \frac { \sqrt { 3 } } { 2 } , - \frac { 1 } { 2 } \right)$ .
C) $t = \frac { 19 \pi } { 3 }$ corresponds to the point $\left( \frac { 1 } { 2 } , - \frac { \sqrt { 3 } } { 2 } \right)$ .
D) $t = \frac { 19 \pi } { 3 }$ corresponds to the point $\left( \frac { 1 } { 2 } , \frac { \sqrt { 3 } } { 2 } \right)$ .
E) $t = \frac { 19 \pi } { 3 }$ corresponds to the point $\left( - \frac { \sqrt { 3 } } { 2 } , - \frac { 1 } { 2 } \right)$ .

Question

Find the point (x,y)on the unit circle that corresponds to the real number t.​ $t = \frac { 19 \pi } { 3 }$ ​
A) $t = \frac { 19 \pi } { 3 }$ corresponds to the point $\left( \frac { \sqrt { 3 } } { 2 } , \frac { 1 } { 2 } \right)$ .
B) $t = \frac { 19 \pi } { 3 }$ corresponds to the point $\left( \frac { \sqrt { 3 } } { 2 } , - \frac { 1 } { 2 } \right)$ .
C) $t = \frac { 19 \pi } { 3 }$ corresponds to the point $\left( \frac { 1 } { 2 } , - \frac { \sqrt { 3 } } { 2 } \right)$ .
D) $t = \frac { 19 \pi } { 3 }$ corresponds to the point $\left( \frac { 1 } { 2 } , \frac { \sqrt { 3 } } { 2 } \right)$ .
E) $t = \frac { 19 \pi } { 3 }$ corresponds to the point $\left( - \frac { \sqrt { 3 } } { 2 } , - \frac { 1 } { 2 } \right)$ .

Quizplus · Accepted Answer

The real number t in binary represents 3π/4 radians. On the unit circle, this corresponds to the point (-√2/2, √2/2) or (cos(3π/4), sin(3π/4)). The correct option is D, which has the hexadecimal representation of this point.

Find the Point (X,y)on the Unit Circle That Corresponds to the Real