Solve the following equation. $\cos ^ { 2 } x + \cos x = 0$
A) $x = \frac { 3 \pi } { 4 } + n \pi \text { and } x = \frac { 5 \pi } { 4 } + n \pi$ ,where n is an integer
B) $x = \pi + 2 n \pi \text { and } x = \frac { \pi } { 2 } + n \pi$ ,where n is an integer
C) $x = \frac { 3 \pi } { 4 } + 2 n \pi \text { and } x = \frac { 5 \pi } { 4 } + 2 n \pi$ ,where n is an integer
D) $x = n \pi \text { and } x = \frac { 3 \pi } { 2 } + n \pi$ ,where n is an integer
E) $x = \pi + n \pi \text { and } x = \frac { \pi } { 2 } + 2 n \pi$ ,where n is an integer

Question

Solve the following equation.​ $\cos ^ { 2 } x + \cos x = 0$ ​
A)​ $x = \frac { 3 \pi } { 4 } + n \pi \text { and } x = \frac { 5 \pi } { 4 } + n \pi$ ,where n is an integer
B)​ $x = \pi + 2 n \pi \text { and } x = \frac { \pi } { 2 } + n \pi$ ,where n is an integer
C)​ $x = \frac { 3 \pi } { 4 } + 2 n \pi \text { and } x = \frac { 5 \pi } { 4 } + 2 n \pi$ ,where n is an integer
D)​ $x = n \pi \text { and } x = \frac { 3 \pi } { 2 } + n \pi$ ,where n is an integer
E)​ $x = \pi + n \pi \text { and } x = \frac { \pi } { 2 } + 2 n \pi$ ,where n is an integer

Quizplus · Accepted Answer

The Answer of Solve the following equation.​ $\cos ^ { 2 } x + \cos x = 0$ ​
A)​ $x = \frac { 3 \pi } { 4 } + n \pi \text { and } x = \frac { 5 \pi } { 4 } + n \pi$ ,where n is an integer
B)​ $x = \pi + 2 n \pi \text { and } x = \frac { \pi } { 2 } + n \pi$ ,where n is an integer
C)​ $x = \frac { 3 \pi } { 4 } + 2 n \pi \text { and } x = \frac { 5 \pi } { 4 } + 2 n \pi$ ,where n is an integer
D)​ $x = n \pi \text { and } x = \frac { 3 \pi } { 2 } + n \pi$ ,where n is an integer
E)​ $x = \pi + n \pi \text { and } x = \frac { \pi } { 2 } + 2 n \pi$ ,where n is an integer

Solve the Following Equation cos⁡2x+cos⁡x=0\cos ^ { 2 } x + \cos x = 0cos2x+cosx=0

Solve the Following Equation $\cos ^ { 2 } x + \cos x = 0$