Solve the system of equations by graphing. $$\left\{ \begin{array} { l }
2 x + 3 y = 28 \
6 x + 5 y = 60
\end{array} \right.$$
A)(-6,5)
B)(3,- 5)
C)(5,6)
D)(2,6)
E)(5,3)

Question

​Solve the system of equations by graphing.​ $$\left\{ \begin{array} { l } 
2 x + 3 y = 28 \
6 x + 5 y = 60
\end{array} \right.$$ ​ ​
A)(-6,5)
B)​(3,- 5)
C)​(5,6)
D)​(2,6)
E)​(5,3)

Quizplus · Accepted Answer

To solve the system of equations by graphing, we first rearrange each equation into slope-intercept form (y = mx + b). For the first equation, $2x + 3y = 28$, we get $y = -\frac{2}{3}x + \frac{28}{3}$. For the second equation, $6x + 5y = 60$, we get $y = -\frac{6}{5}x + 12$. Graphing these two lines, we look for the point where they intersect. The correct intersection point that satisfies both equations is (5,6), which corresponds to choice C.

​Solve the System of Equations by Graphing {2x+3y=286x+5y=60\left\{ \begin{array} { l } 2 x + 3 y = 28 \\6 x + 5 y = 60\end{array} \right.{2x+3y=286x+5y=60​

Solve the System of Equations by Graphing $\left\{ \begin{array} { l } 2 x + 3 y = 28 \\6 x + 5 y = 60\end{array} \right.$