Solve the system by the method of substitution. $$\left\{ \begin{array} { l }
\frac { 1 } { 10 } x + \frac { 3 } { 10 } y = 1 \\
- \frac { 1 } { 5 } x + \frac { 2 } { 5 } y = 1
\end{array} \right.$$
A)(-1,-3)
B)(-3,1)
C)(1,-3)
D)(3,1)
E)(1,3)

Question

​Solve the system by the method of substitution. ​​ $$\left\{ \begin{array} { l } 
\frac { 1 } { 10 } x + \frac { 3 } { 10 } y = 1 \\
- \frac { 1 } { 5 } x + \frac { 2 } { 5 } y = 1
\end{array} \right.$$ ​
A)​(-1,-3)
B)​(-3,1)
C)​(1,-3)
D)​(3,1)
E)​(1,3)

Quizplus · Accepted Answer

The Answer of ​Solve the system by the method of substitution. ​​ $$\left\{ \begin{array} { l } 
\frac { 1 } { 10 } x + \frac { 3 } { 10 } y = 1 \\
- \frac { 1 } { 5 } x + \frac { 2 } { 5 } y = 1
\end{array} \right.$$ ​
A)​(-1,-3)
B)​(-3,1)
C)​(1,-3)
D)​(3,1)
E)​(1,3)

​Solve the System by the Method of Substitution {110x+310y=1−15x+25y=1\left\{ \begin{array} { l } \frac { 1 } { 10 } x + \frac { 3 } { 10 } y = 1 \\\\- \frac { 1 } { 5 } x + \frac { 2 } { 5 } y = 1\end{array} \right.⎩⎨⎧​101​x+103​y=1−51​x+52​y=1​

Solve the System by the Method of Substitution $\left\{ \begin{array} { l } \frac { 1 } { 10 } x + \frac { 3 } { 10 } y = 1 \\\\- \frac { 1 } { 5 } x + \frac { 2 } { 5 } y = 1\end{array} \right.$