Solve the System by the Method of Substitution $$\left\{ \begin{array} { r } 7 x + y = 3 \\x ^ { 3 } - 3 + y = 0\end{array} \right.$$

Solve the system by the method of substitution.Check your solution(s) graphically.​ $$\left\{ \begin{array} { r } 7 x + y = 3 \\x ^ { 3 } - 3 + y = 0\end{array} \right.$$ ​ ​

A) $( \sqrt { 7 } , 3 + 7 \sqrt { 7 } ) , ( 0,3 ) , ( \sqrt { 7 } , 3 - 7 \sqrt { 7 } )$
B) $( - \sqrt { 7 } , 3 + 7 \sqrt { 7 } ) , ( 0 , - 3 ) , ( \sqrt { 7 } , 3 - 7 \sqrt { 7 } )$
C) $( - \sqrt { 7 } , 3 - 7 \sqrt { 7 } ) , ( 0,3 ) , ( \sqrt { 7 } , 3 - 7 \sqrt { 7 } )$
D) $( - \sqrt { 7 } , 3 + 7 \sqrt { 7 } ) , ( 0,3 ) , ( \sqrt { 7 } , 3 + 7 \sqrt { 7 } )$
E) $( - \sqrt { 7 } , 3 + 7 \sqrt { 7 } ) , ( 0,3 ) , ( \sqrt { 7 } , 3 - 7 \sqrt { 7 } )$