Find the indefinite integral.
-$\int \cos ( \pi - 3 x )$ dx
A) $\frac { 1 } { 3 }$ sin (π - 3x) + C
B) - $\frac { 1 } { 3 }$ sin (π - 3x) + C
C) 3 cos (π- 3x) + C
D) -sin (π - 3x) + C
E) none of these

Question

Find the indefinite integral. 
-$\int \cos ( \pi - 3 x )$ dx
A) $\frac { 1 } { 3 }$ sin (π - 3x) + C
B) - $\frac { 1 } { 3 }$ sin (π - 3x) + C
C) 3 cos (π- 3x) + C
D) -sin (π - 3x) + C
E) none of these

Quizplus · Accepted Answer

The integral of $\cos(\pi - 3x)$ with respect to $x$ is $\frac{1}{-3}\sin(\pi - 3x) + C$, because when you differentiate $\sin(\pi - 3x)$, you get $\cos(\pi - 3x)$ multiplied by the derivative of $(\pi - 3x)$ with respect to $x$, which is $-3$. Therefore, integrating gives the opposite effect, dividing by $-3$, leading to choice B.

Find the Indefinite Integral ∫cos⁡(π−3x)\int \cos ( \pi - 3 x )∫cos(π−3x)

Find the Indefinite Integral $\int \cos ( \pi - 3 x )$