Find the indefinite integral.
-$\int \sin 2 t d t$
A) - $\frac { 1 } { 2 }$ cos 2t + C
B) -cos t + C
C) - $\frac { 1 } { 2 }$ cos t + C
D) -2 cos 2t + C

Name: Find the indefinite integral. -$\int \sin 2 t d t$ A) - $\frac { 1 } { 2 }$ cos 2t + C B) -cos t + C C) - $\frac { 1 } { 2 }$ cos t + C D) -2 cos 2t + C
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Question

Find the indefinite integral. 
-$\int \sin 2 t d t$
A) - $\frac { 1 } { 2 }$ cos 2t + C
B) -cos t + C
C) - $\frac { 1 } { 2 }$ cos t + C
D) -2 cos 2t + C

Quizplus · Accepted Answer

The integral of $\sin 2t$ with respect to $t$ is $-\frac{1}{2} \cos 2t + C$, using the integral formula $\int \sin ax \, dx = -\frac{1}{a} \cos ax + C$, where $a = 2$.

Find the Indefinite Integral ∫sin⁡2tdt\int \sin 2 t d t∫sin2tdt A) -

Find the Indefinite Integral $\int \sin 2 t d t$ A) -