Find the right part of the equality. $$4 + 5 + 6 + \cdots + ( n + 3 ) =$$
A) $\frac { n ( 8 n + 7 ) } { 3 }$
B) $\frac { n ( n + 7 ) } { 2 }$
C) $\frac { n ( 5 n + 7 ) } { 3 }$
D) $n ( 5 n - 1 )$
E) $\frac { n ( n + 7 ) } { n }$

Name: Find the right part of the equality. \[4 + 5 + 6 + \cdots + ( n + 3 ) =\] A) $\frac { n ( 8 n + 7 ) } { 3 }$ B) $\frac { n ( n + 7 ) } { 2 }$ C) $\frac { n ( 5 n + 7 ) } { 3 }$ D) $n ( 5 n - 1 )$ E) $\frac { n ( n + 7 ) } { n }$
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The Answer is B

Find the Right Part of the Equality 4+5+6+⋯+(n+3)=4 + 5 + 6 + \cdots + ( n + 3 ) =4+5+6+⋯+(n+3)=

Find the Right Part of the Equality $4 + 5 + 6 + \cdots + ( n + 3 ) =$