Calculate the kinetic energy of an electron moving at 0.737 c.Express your answer in keV.
A)250 keV
B)210 keV
C)280 keV
D)320 keV

Question

Quizplus · Accepted Answer

The kinetic energy of an electron moving at 0.737 c is given by:$$K = (\gamma - 1)mc^2$$where $\gamma$ is the Lorentz factor, $m$ is the mass of the electron, and $c$ is the speed of light.Substituting the given values, we get:$$\gamma = \frac{1}{\sqrt{1 - v^2/c^2}} = \frac{1}{\sqrt{1 - 0.737^2}} = 1.52$$$$K = (1.52 - 1)(511 keV) = 250 keV$$Therefore, the correct answer is A.

Calculate the Kinetic Energy of an Electron Moving at 0